Time Response of First-order Systems

Submitted by pradipta pramanik on Mon, 07/25/2011 - 08:45

1sT

C(s)R(s)=G(s)1+G(s)

G(s)=1sT

C(s)R(s)=1sT1+1sT=1sT+1

C(s)=(1sT+1)R(s)

 

C(s)=(1sT+1)R(s)

 

R(s)

C(s)

C(s).

r(t)=δ(t)

R(s)=1

C(s)=(1sT+1)R(s)

R(s)=1

C(s)=(1sT+1)(1)=1sT+1

C(s)=1T( s+1T)C(s)=1T(1s+1T)

c(t)=1Te(tT)u(t)

r(t)=u(t)

R(s)=1s

C(s)=(1sT+1)R(s)

R(s)=1s

C(s)=(1sT+1)(1s)=1s(sT+1)

C(s)=1s(sT+1)=As+BsT+1

1s(sT+1)=A(sT+1)+Bss(sT+1)

1=A(sT+1)+Bs

0=T+BB=T

C(s).

C(s)=1sTsT+1=1sTT(s+1T)

C(s)=1s1s+1T

c(t)=(1e(tT))u(t)

ctr(t)=e(tT)u(t)

css(t)=u(t)

So,r(t)=tu(t)

R(s)=1s2

C(s)=(1sT+1)R(s)

R(s)=1s2

C(s)=(1sT+1)(1s2)=1s2(sT+1)

C(s).

C(s)=1s2(sT+1)=As2+Bs+CsT+1

1s2(sT+1)=A(sT+1)+Bs(sT+1)+Cs2s2(sT+1)

1=A(sT+1)+Bs(sT+1)+Cs2

0=T+BB=T

s2 C=T2.

C=T2

C(s).

C(s)=1s2Ts+T2sT+1=1s2Ts+T2T(s+1T)

C(s)=1s2Ts+Ts+1T

c(t)=(tT+Te(tT))u(t)

ctr(t)=Te(tT)u(t)

css(t)=(tT)u(t)

r(t)=t22u(t)

R(s)=1s3

C(s)=(1sT+1)R(s)

R(s)=1s3

C(s)=(1sT+1)(1s3)=1s3(sT+1)

C(s).

C(s)=1s3(sT+1)=As3+Bs2+Cs+DsT+1

T,T2andT3

C(s)=1s3Ts2+T2sT3sT+1C(s)=1s3Ts2+T2sT2s+1T

c(t)=(t22Tt+T2T2e(tT))u(t)

Ctr(t)=T2e(tT)u(t)

Css(t)=(t22Tt+T2)u(t)