Submitted by Anonymous (not verified) on Fri, 08/05/2011 - 01:32

˙X=AX+BU

Y=CX+DU

sX(s)=AX(s)+BU(s)

(sIA)X(s)=BU(s)

X(s)=(sIA)1BU(s)

Y(s)=CX(s)+DU(s)

Y(s)=C(sIA)1BU(s)+DU(s)

Y(s)=[C(sIA)1B+D]U(s)

Y(s)U(s)=C(sIA)1B+D

Y(s)U(s)=C(sIA)1B