For the circuit shown, what is the voltage V if the source voltage is reduced by 50%?
a. IR + E
b. E – IR
c. 2IR – (E/2)
d. (E/2) – IR
For the circuit shown, what is the voltage V if the source voltage is reduced by 50%?
a. IR + E
b. E – IR
c. 2IR – (E/2)
d. (E/2) – IR
Answer : d.
for without voltage reduction V=E-IR
when voltage is reduced then Enew=E/2-IR