Solution To Problem 0001 | Higher Secondary Physics | BengalStudents

Problem 0001

A shell of mass m is at rest initially. It explodes into three fragments having masses in the ratio 2 : 2 : 1. The fragments having equal masses fly off along mutually perpendicular direction with speed v. What willl be the speed of the third (lighter) fragment?

Answer:

From conservation of momentum

$m{v_3} + 2\sqrt 2 vm=0$

${v_3} = -2\sqrt 2 v$

Hence, Speed of third fragment is $2\sqrt 2 v$

Log in or register to post comments
10 views

Tags

wbjee 2011

Comments

Related Items

WBJEE 2011 Seat Status on 31.07.2011 Counselling upto GEN 43200 rank

JEM Seat Allotment status of 2011
Category : GEN
Last Updated: 31/07/2011 , 18:29:44

WBJEE 2011 Seat Status on 27.07.2011 Counselling upto GEN 22400 rank

JEM Seat Allotment status of 2011
Category : GEN
Last Updated: 27/07/2011 , 18:42:21

WBJEE 2011 Seat Status on 24.07.2011 Counselling upto GEN 10400 rank

Counselling upto GEN 10400

JEM Seat Allotment status of 2011
Category : GEN
Last Updated: 24/07/2011 , 18:49:04

WBJEE 2011 Seat Status on 26.07.2011 Counselling upto GEN 18400 rank

JEM Seat Allotment status of 2011
Category : GEN
Last Updated: 26/07/2011 , 18:35:49

WBJEE 2011 Seat Status on 22.07.2011 Counselling upto GEN 3200 rank

JEM Seat Allotment status of 2011
Category : GEN
Last Updated: 22/07/2011 , 19:42:27

Status after Counselling of Rank:-GEN-1 to GEN-3200