Submitted by Sudeepta Pramanik on Fri, 06/17/2011 - 19:29

RESISTOR:

ResistorResistor is energy absorbing element in electrical circuit. It's unit is ohm.

The potential difference v across the terminals of resistor R, is directly proportional to the current i flowing through it.

That is,

           V=IR; Here R is called the resistance of resistor R

The reciprocal of resistance is defined as conductance( G).

Hence,

         (1/R)=G    &     I=VG

The power absorbed by a resistor is given by

         P=VI

 

INDUCTOR:

inductorInductor is an energy storing element in electrical circuit. It's unit is henry.

The potential difference v across the terminals of inductor is directly proportional to rate of change of current through it.

That is, [tex]V = L\frac{{di}}{{dt}}[/tex]; Here the term L is the proportionality constant and known as inductance of the inductor.

Hence, current through inductor is

                                                     [tex]I = \frac{1}{L}\int\limits_0^t {} Vdt + I(0)[/tex]

Where I(0) is the initial current of the inductor.

The energy stored in an inductor over the interval [tex]\left( {{t_1},{t_2}} \right)[/tex] is,

        [tex]E\left( {{t_1},{t_2}} \right) = \int\limits_{{t_1}}^{{t_2}} {VIdt = \int\limits_{{t_1}}^{{t_2}} {L(dI/dt)} } Idt = \frac{L}{2}[\mathop I\nolimits^2 ({t_2})\_\mathop I\nolimits^2 ({t_1})][/tex]

Inductor store the energy in the form of current.

    

CAPACITOR:

capacitorCapacitor is another energy storing element in electrical circuit. It's unit is farad.

The potential difference v between the terminals of capacitor is proportional to the charge q on it. That is

                                                                          [tex]v \propto q[/tex]

                                                                           v=q/C; where C is the proportionality constant and is called the capacitance.

Now, [tex]i = \frac{{dq}}{{dt}} = C(\frac{{dv}}{{dt}})[/tex]

         [tex]\int {dv = \frac{1}{C}\int {idt} } [/tex]

Hence, [tex]V(t) = \frac{1}{C}\int\limits_0^t {i(t)dt}  + q(0)/C[/tex]

where q(0) is the initial charge across the capacitor C.

The energy stored in a capacitor over the interval [tex]\left( {{t_1},{t_2}} \right)[/tex] is,

[tex]E\left( {{t_1},{t_2}} \right) = \int\limits_{{t_1}}^{{t_2}} {VIdt = \int\limits_{{t_1}}^{{t_2}} {VC(dv/dt)} } dt = \frac{C}{2}[\mathop V\nolimits^2 ({t_2})\_\mathop V\nolimits^2 ({t_1})][/tex]

Capacitor store the energy in the form of voltage.

 

 

Comments

Related Items

Kirchhoff's Laws

Kirchhoff's laws simply deal with voltage drops and rises with the current flowing in a circuit by using the ideas of simple energy conservation. These laws are very helpful in determining of the output response for network analysis.